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Chemistry 352

Hund's Coupling Cases (a) and (b)

Hund’s Coupling Cases for Diatomic Molecules

In diatomic molecules, electronic angular momenta can couple to the internuclear axis in different ways depending on the relative strengths of spin–orbit coupling and rotational motion. These limiting behaviors are described by Hund’s coupling cases. The most common cases for light and moderately heavy diatomic molecules are Hund’s case (a) and Hund’s case (b).

Hund’s cases are idealized limits: real molecules may lie between them, but the cases provide a powerful framework for constructing term symbols, predicting level structure, and understanding spectra.

Hund’s Case (a): Strong Spin–Orbit Coupling

Hund’s case (a) applies when spin–orbit coupling is strong compared to rotational energy. In this limit, both the electronic orbital angular momentum and the electron spin are strongly tied to the internuclear axis.

In case (a), \(\Omega\) is a good quantum number, and molecular term symbols are written as \({}^{2S+1}\Lambda_{\Omega}\) (with additional parity and symmetry labels added later).

Hund’s cases (a) and (b) angular momentum vectors diagram

Hund’s coupling case (a): electronic orbital and spin angular momenta (Λ, Σ) couple strongly to the molecular axis, giving Ω = Λ + Σ; rotation R then couples to form the total J.

Hund’s Case (b): Weak Spin–Orbit Coupling

Hund’s case (b) applies when spin–orbit coupling is weak compared to rotational energy. In this limit, the electronic orbital angular momentum remains coupled to the internuclear axis, but the electron spin does not.

In case (b), \(\Omega\) is not a good quantum number. Levels are instead labeled by \(N\) and \(J = N+S,\,N+S-1,\ldots,|N-S|\).

Summary: Hund’s case (a) emphasizes coupling to the molecular axis (\(\Lambda, \Sigma, \Omega\) good), while Hund’s case (b) emphasizes rotational coupling (\(\Lambda, N, J\) good). Identifying the appropriate case is the first step in interpreting diatomic molecular spectra.

Practice: Hund's coupling cases (a) & (b)

Click Am I right? to grade each question.

Problem 1
A diatomic molecule shows strong spin–orbit splitting, and the observed energy levels are best labeled by a well-defined value of Ω. Which Hund’s coupling case best describes this molecule?
A. Hund’s case (a)
B. Hund’s case (b)
C. Free-atom LS coupling
D. Rotationally uncoupled limit
Problem 2
Which set of quantum numbers is most appropriate for labeling energy levels in Hund’s case (b)?
A. \( \Lambda, \Sigma, \Omega \)
B. \( \Lambda, N, J \)
C. \( \Sigma, \Omega, J \)
D. \( \Lambda, \Sigma, J \)
Problem 3
In Hund’s case (a), why is \( \Omega \) a good quantum number?
A. Because molecular rotation is negligible
B. Because electron spin is uncoupled from orbital motion
C. Because both \( \Lambda \) and \( \Sigma \) are strongly coupled to the internuclear axis
D. Because \( \Omega \) is conserved in all molecules
Problem 4
Which statement correctly contrasts Hund’s case (a) and Hund’s case (b)?
A. In case (a), spin couples to rotation; in case (b), spin couples to the axis
B. In case (a), \( \Lambda \) is not a good quantum number
C. In case (b), spin–orbit coupling is weak compared to rotational energy
D. In case (b), \( \Omega \) is always conserved
Problem 5
In Hund’s case (b), the total angular momentum is constructed as \( \mathbf{J} = \; ? \)
A. \( \mathbf{L} + \mathbf{S} \)
B. \( \mathbf{R} + \mathbf{L} \)
C. \( \mathbf{N} + \mathbf{S} \)
D. \( \mathbf{\Omega} + \mathbf{R} \)
Problem 6
Diagram:
left panel right panel
Question: Which panel in the diagram corresponds to Hund’s case (a)?
A. Left panel
B. Right panel
C. Both panels represent case (a)
D. Neither panel represents case (a)

Key points (one glance)

Big picture: Hund’s cases provide the bridge between atomic angular momentum ideas and molecular spectra. Identifying whether a diatomic molecule is closer to case (a) or case (b) determines which quantum numbers are meaningful, how energy levels are organized, and how molecular spectra should be interpreted.