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Chemistry 352

Using the Quantum Defect

While hydrogen-like atoms follow an ideal \(1/n^2\) energy pattern, real (polyelectronic) atoms show small but systematic deviations from this behavior. These deviations arise because the excited electron can partially penetrate the inner electron cloud and experience a stronger nuclear attraction.

This effect is captured using the concept of a quantum defect, which provides a powerful method for determining the ionization potential of an atom from its Rydberg series.


The quantum defect formulation

The energy of a Rydberg level is written as

\[ E(n) = \mathrm{IP} - \frac{R_M}{(n^*)^2}, \]

where:

The effective principal quantum number is defined as

\[ n^* = n - \delta, \]

where \(\delta\) is the quantum defect for the given Rydberg series (typically fixed for a given \(\ell\) value).

For highly excited states, the quantum defect becomes nearly independent of \(n\), reflecting the fact that the Rydberg electron spends most of its time far from the atomic core.


Determining the ionization potential

The ionization potential can be extracted by finding the value of \(\mathrm{IP}\) that makes the quantum defect \(\delta\) constant at high excitation. This is done using an iterative procedure:

  1. Assign the principal quantum number \(n\) to each observed Rydberg level.
  2. Choose an initial guess for the ionization potential \(\mathrm{IP}\).
  3. Using this guess, compute the effective principal quantum number \(n^*\) for each level from \(E(n)=\mathrm{IP}-R_M/(n^*)^2\).
  4. Determine the quantum defect for each level using \(\delta = n - n^*\).
  5. Plot \(\delta\) as a function of \(n\) to assess whether the defect is approximately constant at high \(n\).
  6. Adjust the guess for the ionization potential and repeat the process until the quantum defect becomes flat (independent of \(n\)) for the most highly excited states.

Physical interpretation

When the correct ionization potential is used, all high-lying Rydberg states in a given series converge smoothly toward the same limit, and the quantum defect reflects the penetration of the electron into the atomic core.

Different orbital angular momentum states (\(s,p,d,\ldots\)) have different quantum defects, but each defect becomes nearly constant at sufficiently large \(n\).

Applet: Ionization potential from quantum defects (Na I, \(np\ ^2P_{1/2}\))

Enter a guess for the ionization potential (series limit) in \(\text{cm}^{-1}\). The applet computes the effective principal quantum number \(n^*\), the quantum defect \(\delta = n-n^*\), and plots \(\delta\) vs. \(n\). A good IP guess makes \(\delta\) approximately constant at high \(n\).


Converted IP:
Using \(1\ \text{eV} = 8065.544\ \text{cm}^{-1}\)

n \(E(n)\) (\(\text{cm}^{-1}\)) \(\Delta E = \mathrm{IP}-E(n)\) (\(\text{cm}^{-1}\)) \(n^*=\sqrt{R_M/\Delta E}\) \(\delta=n-n^*\)

Data: Na I \(np\ ^2P_{1/2}\) term values (in \(\text{cm}^{-1}\)) for \(n=3\ldots 12\).

Big idea: by adjusting the ionization potential until the quantum defect becomes constant for highly excited states, experimental Rydberg spectra can be used to determine accurate ionization energies for real atoms.

Your turn

Problem 1
What is the physical meaning of the quantum defect \(\delta\) in a Rydberg series?
The error in the measured energy levels
The deviation from ideal hydrogen-like behavior due to core penetration
The reduced mass correction to the Rydberg constant
The shielding constant from Slater’s rules
Problem 2
In the quantum defect expression \(E(n)=\mathrm{IP}-\dfrac{R_M}{(n^*)^2}\), what quantity must be adjusted to make \(\delta\) nearly constant at high \(n\)?
The ionization potential
The Rydberg constant
The principal quantum number
The angular momentum quantum number
Problem 3
Suppose your guessed ionization potential is too low. What behavior would you expect in a plot of \(\delta\) versus \(n\)?
The quantum defect will be perfectly flat
The quantum defect will increase with \(n\)
The quantum defect will decrease with \(n\)
The quantum defect will be exactly zero
Problem 4
Why does the quantum defect become nearly constant at high \(n\)?
The electron’s angular momentum increases
The nuclear charge is reduced
The Rydberg constant becomes exact
The Rydberg electron spends most of its time far from the atomic core

Key points (one glance)

Big picture: the quantum defect method turns small deviations from hydrogen-like behavior into a powerful diagnostic tool, enabling precise determination of ionization potentials for real atoms.