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Chemistry 352

The Photoelectric Effect

Light as particles

Why classical wave theory failed — and photons were required.

The photoelectric effect refers to the emission of electrons from a metal surface when light of sufficiently high frequency shines on it. This phenomenon played a crucial role in the development of quantum mechanics because it cannot be explained using classical wave theory.

In a typical photoelectric experiment, light of known frequency is directed onto a clean metal surface, and the kinetic energy of the emitted electrons is measured. Several key experimental observations emerge.


Key experimental observations

These observations directly contradict classical wave predictions, which suggested that energy should depend only on light intensity.


Einstein’s explanation: photons

In 1905, Einstein explained the photoelectric effect by proposing that light consists of discrete packets of energy called photons. Each photon carries an energy

\[ E = h\nu, \]

where \(h\) is Planck’s constant and \( \nu \) is the frequency of the light.

In the photoelectric effect, a single photon transfers its energy to a single electron. Part of this energy is used to overcome the attraction holding the electron in the metal. The remaining energy appears as kinetic energy of the emitted electron.


Work function and kinetic energy

The minimum energy required to remove an electron from the metal is called the work function, denoted \( \phi \). Energy conservation gives

\[ h\nu = \phi + K_{\text{max}}, \]

where \( K_{\text{max}} \) is the maximum kinetic energy of the emitted electrons.

If \( h\nu < \phi \), no electrons are emitted. The threshold frequency is therefore

\[ \nu_0 = \frac{\phi}{h}. \]

This equation explains why frequency, not intensity, determines whether emission occurs.

Big idea: the photoelectric effect demonstrates that light behaves as particles with quantized energy, providing direct evidence for the photon model of radiation.

Your turn

Problem 1
Which statement best describes the threshold frequency in the photoelectric effect?
The frequency that produces the maximum number of electrons The minimum frequency required to eject electrons from the metal The frequency that produces the brightest light The frequency at which intensity no longer matters
Problem 2
For light with frequency \( \nu > \nu_0 \), what happens if the intensity of the light is increased (while keeping \( \nu \) constant)?
The maximum kinetic energy increases The maximum kinetic energy decreases More electrons are emitted, but \(K_{\max}\) stays the same Electrons stop being emitted
Problem 3
A metal has a work function \( \phi \). Light of frequency \( \nu \) shines on the metal. Which expression gives the maximum kinetic energy of the emitted electrons?
\( K_{\max} = h\nu + \phi \) \( K_{\max} = \phi - h\nu \) \( K_{\max} = h\nu - \phi \) \( K_{\max} = \frac{\phi}{h\nu} \) \( K_{\max} = \frac{h\nu}{\phi} \)
Problem 4
Which equation correctly relates the threshold frequency \( \nu_0 \) to the work function \( \phi \)?
\( \nu_0 = \frac{h}{\phi} \) \( \nu_0 = \frac{\phi}{h} \) \( \nu_0 = \phi h \) \( \nu_0 = \frac{\phi}{hc} \)

Key points (one glance)