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Chemistry 352

Properties of Light

Fundamental relations

Light (electromagnetic radiation) is characterized by its wavelength \( \lambda \) (m), frequency \( \nu \) (Hz), and the energy per photon \( E \) (J). The two central relations are

\[ c = \lambda\,\nu \]

\[ E = h\,\nu \]

Here \( c \) is the speed of light in vacuum and \( h \) is Planck’s constant. Using these two relations together lets you convert between any two of \( \lambda \), \( \nu \), and \( E \).

Useful derived forms

Replace \( \nu = c/\lambda \) into \( E=h\nu \) to get energy in terms of wavelength:

\[ E = \frac{h c}{\lambda}. \]

It’s often convenient to work in electronvolts and nanometres. Useful constants (SI and derived):

ConstantValuePractical Value
Speed of light \(c\)\(2.99792458\times10^8\ \text{m·s}^{-1}\)\(2.998\times10^8\ \text{m·s}^{-1}\)
Planck constant \(h\)\(6.62607015\times10^{-34}\ \text{J·s}\)\(6.626\times10^{-34}\ \text{J·s}\)
Elementary charge \(e\)\(1.602176634\times10^{-19}\ \text{C}=\text{J·eV}^{-1}\)\(1.602\times10^{-19}\ \text{C}=\text{J·eV}^{-1}\)
Product \(hc\)\(1.986445857\times10^{-25}\ \text{J·m}\)\(1.986\times10^{-25}\ \text{J·m}\)
\(hc\) in eV·nm\(\displaystyle \frac{hc}{e}\times10^{9}\approx 1239.841984\ \text{eV·nm}\)\(\displaystyle \frac{hc}{e}\times10^{9}\approx 1240\ \text{eV·nm}\)

Using these values, the photon energy in electronvolts for a wavelength in nm is approximately

\[ E(\text{eV}) \approx \frac{1239.842}{\lambda(\text{nm})}. \]

Quick rearrangements (handy algebra)

\[ \nu = \frac{c}{\lambda}, \qquad \lambda = \frac{c}{\nu}, \qquad E = h\nu = \frac{hc}{\lambda}. \]

You can also express energy in wave-number units (common in spectroscopy). Define the wave number \( \tilde{\nu} = 1/\lambda \) (when \( \lambda \) is in cm, \( \tilde{\nu} \) has units cm\(^{-1}\)):

\[ \tilde{\nu}(\text{cm}^{-1}) = \frac{10^{7}}{\lambda(\text{nm})}. \]

Then \( E \) in J is \( E = h c \tilde{\nu} \) (with \( \tilde{\nu} \) in m\(^{-1}\) or cm\(^{-1}\) using consistent units).

Worked examples

  1. \( \lambda = 500\ \text{nm} \) (green light)
    Frequency: \[ \nu = \frac{c}{\lambda} = \frac{2.99792458\times10^{8}}{500\times10^{-9}} = 5.99584916\times10^{14}\ \text{Hz}. \] Photon energy: \[ E = h\nu = 6.62607015\times10^{-34}\times 5.99584916\times10^{14} = 3.9728917\times10^{-19}\ \text{J} \approx 2.4797\ \text{eV}. \] Wave number (cm\(^{-1}\)): \[ \tilde{\nu} = \frac{10^{7}}{500} = 20000\ \text{cm}^{-1}. \]
  2. \( E = 2.0\ \text{eV} \)
    First convert to joules: \( E=2.0\times1.602176634\times10^{-19}=3.20435327\times10^{-19}\ \text{J} \). Then wavelength: \[ \lambda = \frac{hc}{E} = \frac{1.986445857\times10^{-25}}{3.20435327\times10^{-19}} \approx 620\ \text{nm}. \] Frequency: \[ \nu = \frac{E}{h} \approx \frac{3.20435327\times10^{-19}}{6.62607015\times10^{-34}} \approx 4.83\times10^{14}\ \text{Hz}. \]

Practical notes and common approximations

Question 1
Which equation correctly relates the wavelength \( \lambda \) and frequency \( \nu \) of light in vacuum?
A. \( \lambda = c\nu \) B. \( \nu = c\lambda \) C. \( c = \lambda\nu \) D. \( c = \lambda / \nu \)
Question 2
Two photons have wavelengths of 400 nm and 800 nm. Which statement is correct?
A. The 800 nm photon has twice the energy of the 400 nm photon
B. The 400 nm photon has twice the energy of the 800 nm photon
C. Both photons have the same energy
D. Photon energy depends only on intensity, not wavelength
Question 3
What is the frequency of light with wavelength \( \lambda = 500\ \text{nm} \)? (Take \( c = 3.00\times10^8\ \text{m·s}^{-1} \).)
A. \( 6.0\times10^{11}\ \text{Hz} \) B. \( 6.0\times10^{13}\ \text{Hz} \) C. \( 6.0\times10^{14}\ \text{Hz} \) D. \( 6.0\times10^{16}\ \text{Hz} \)
Question 4
Using \( E(\text{eV}) \approx \dfrac{1240}{\lambda(\text{nm})} \), what is the energy of a photon with \( \lambda = 620\ \text{nm} \)?
A. \( 0.50\ \text{eV} \) B. \( 1.0\ \text{eV} \) C. \( 2.0\ \text{eV} \) D. \( 4.0\ \text{eV} \)
Question 5
To convert directly from wavelength \( \lambda \) to photon energy \( E \), which equation should be used?
A. \( E = h\lambda \) B. \( E = h\nu \) C. \( E = \dfrac{hc}{\lambda} \) D. \( E = \dfrac{c}{\lambda} \)

Key points (one glance)