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Chemistry 111

Units of Measurement

Units of Measurement

The essence of science is the measurement and characterization of the world around us. In order to make sense out of our measurements, there must be a concise and standard language in which we can communicate our measurements. One such language is the International System (SI) of units.

In SI, there are units which are defined (suvh as those for mass, distance, and time) and others which are derived from the defined units. The basic set of derived units base on meters, kilograms, and seconds (mks) are the units of choice in SI. Here are some examples.

Property Unit Symbol mks Units
Length meter m m
Mass kilogram kg kg
Time second s s
Temperature Kelvin K K
Volume cubic meter m3 m3
Force Newton N kg m s-2
Energy joule J kg m2 s-2
Pressure Pascal Pa kg m-1 s-2

Many units are not strictly part of the SI, but are okay to use. Often this is because of simply a matter of convenience. Units which are not SI units but are acceptable to be used along side of SI units include:

Property Unit Symbol
Atomic Mass atomic mass unit u (6.022 x 1023 u = 1 g)
Volume liter L (1000 L = 1 m3
Energy calorie cal (1 cal = 4.184 J)
electron Volt eV (1 eV = 1.60 x 10-19 J)
Amount of Substance mole mol (1 mol = 6.022 x 1023 things)
Example
Question:
How many L are in 3.24 m3?
Solution:
        1000 L
2.34 m3 x -------- = 2340 L
            m3
                        
>

The most common measurements in a chemistry laboratory are of mass and volume. However, many different type of measurements are made and hence many different types of units are necessary.

Oftentimes, it is more convenient to express a measurment in terms of units which are not the standard SI units. For example, a measured volume may be so small, that we need to write it as

volume of aliquot = 0.00234 L

It would be more convenient to define a smaller unit of volume so the number we record in our notebook doesn't need to be so ridiculously tiny. Since SI is based on the metric system, SI uses the same Greek prefixes used in the metric system to define smaller or larger units of measure. In our example above, we might write

volume of aliquot = 2.34 mL

where the symbol mL stands for milliliters. (A milliliter is 1/1000th of a liter.) There are many such Greek prefixes used in science. With the proliferation of personal computers, many of the prefixes are used commonly in everyday langue now as well. While it is easy to joke about these prefixes, there are a number of common Greek prefixes which every chemistry student is expected to know:

Prefix Symbol Value
tera t 1012 1 000 000 000 000
giga g 109 1 000 000 000
Mega M 106 1 000 000
kilo k 103 1 000
hecta h 102 100
Deca D 101 10
deci d 10-1 0.1
centi c 10-2 0.01
milli m 10-3 0.001
micro μ 10-6 0.000 001
nano n 10-9 0.000 000 001
pico p 10-12 0.000 000 000 001
femto m 10-15 0.000 000 000 000 001

A more complete discussion of the origins of these roots is also available.

Converting between units using Greek prefixes is actually quite easy. For example:

Example
Question: How many femtoseconds are in a millisecond?
Solution:
                            10-3 s       1 fs
                    1 ms x --------- x --------- = 1012 fs    
                            1 ms       10-15 s
Note: Pay attention to how the units are cancelled in the above example. The easiest way to prevent silly errors in calculations is to be meticulous with the use of units. The easiest way to generate silly and frustrating errors is to leave units off of calculations. Omitting units is a very bad habit. Don't get into it. You'll be glad later on!
How many μL in a mL?
10 103 10-3
How many Gs in 10 ms?
107 10-6 10-11
37 cm is how many hm?
3.7 x 10-3 3700 270.3

Some units are defined in terms of others. For example, one liter was originally defined as the volume occupied by a cube with an edge length of 1 dm. This definition allows us to write a very useful conversion factor:

1 L = 1 dm3

Example
Question: What is the edge length (in cm) of a cube which has a volume of 22.4 L?
Solution:
                                1 dm3     103 cm3
                    22.4 L x ------- x --------- = 22 400 cm3      
                                1 L      13 dm3
                
                
                    (22 400 cm3)1/3 = 28.8 cm
Note: Pay attention to how the units are cancelled when powers of units are involved. This situation is common. There are not 10 cm3 in 1 dm3. There are 1000 cm3 in 1 dm3! (1000 = 103.) Raising the unit to a power requires raising the conversion factor to the same power in order to properly cancel the units.

There are many important relationships between units which every chemistry student should know.

Some defined relationships between units
A gram is the mass of 1 mL of water at 3.96 oC. 1 g water = 1 mL (at 3.96 oC)
A Newton is the force necessary to accelerate 1 kg by 1 m/s2. 1 N = 1 kg m s-2
A Joule is the energy required to accelerate 1 kg by 1 m/s2 over a distance of 1 m. 1 J = 1 kg m2 s-2 = 1 N m
A Pascal is the pressure generated by a force of 1 N when spread out over an area of 1 m2. 1 Pa = 1 N m-2 = 1 J s-2 = 1 kg m-1 s-2

Other important relationships are used to relate physical properties to basic units although they do not define units themselves.

Some important physical relationships
Definition
Typical Units
Velocity is given by the distance traveled per unit time. v = distance/time m s-1
N kg-1 s
J kg-1 m-1 s
Momentum is given by the mass times the velocity of an object. p = mv kg m s-1
N s
J m-1 s
Kinetic energy is given by one half the mass times the velocity squared. K.E = 1/2 mv2 kg m2 s-2
N m
J

Now try some problems! You may find it necessary to look up some of the required formulae in a math text. You will be expected to know these. Be careful to properly cancel all units. You'll be glad you did!

Problem 1
1) What is the radius of a circle of area 1.00 m2? What is the circumference?
0.564 cm, 3.54 cm 56.4 cm, 354 cm 177 cm, 11.1 m
Problem 2
2) What is the radius of a sphere of volume 1.00 m3? What is the surface area?
62.0 cm, 4.84 m2 62.0 cm, 390 cm2 100 cm, 1.26 m2
Problem 3
3) What is the mass of water needed to fill a sphere of radius 10.0 cm?
(assume the same density of water as at 3.96 oC)
13.3 kg 1.33 kg 0.0133 kg
Problem 4
4) What force spread over an area of 3.00 m2 would be necessary to generate a standard atmosphere of pressure?
(1 atm = 101.325 kPa)
58500 kN 58.5 kN 304 kN
Problem 5
5) Given an acceleration due to gravity of 9.8 m/s2, what mass (in kg) would be required to generate the force in problem 4?
31.0 kg 5.97 kg 5970 kg